X^2+3x=1038

Solution for X^2+3x=1038 equation:

X^2+3X=1038

We move all terms to the left:

X^2+3X-(1038)=0

a = 1; b = 3; c = -1038;
Δ = b2-4ac
Δ = 32-4·1·(-1038)
Δ = 4161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{4161}}{2*1}=\frac{-3-\sqrt{4161}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{4161}}{2*1}=\frac{-3+\sqrt{4161}}{2}
$